SI-7402 List extends Serializable

While we are all aware of the issues around Serialization,
I think in this case it is perfectly sound and safe to make
List serializable:

- List is not an interface, it is the base type of an ADT.
  Common behavior of its members should be reflected in the base type.
- List is sealed, there is no chance of an user providing a new
  non-serializable subtype of List.

1 files changed, 2 insertions, 1 deletions

diff --git a/test/files/run/lub-visibility.check b/test/files/run/lub-visibility.check
index f3a6bef215..50a0cadebf 100644
--- a/test/files/run/lub-visibility.check
+++ b/test/files/run/lub-visibility.check
@@ -8,7 +8,8 @@ scala> // should infer List[scala.collection.immutable.Seq[Nothing]]
 scala> // but reverted that for SI-5534.
 
 scala> val x = List(List(), Vector())
-x: List[scala.collection.immutable.Seq[Nothing] with scala.collection.AbstractSeq[Nothing]{def companion: scala.collection.generic.GenericCompanion[scala.collection.immutable.Seq with scala.collection.AbstractSeq]; def dropRight(n: Int): scala.collection.immutable.Seq[Nothing] with scala.collection.AbstractSeq[Nothing]{def companion: scala.collection.generic.GenericCompanion[scala.collection.immutable.Seq with scala.collection.AbstractSeq]; def dropRight(n: Int): scala.collection.immutable.Seq[Nothing] with scala.collection.AbstractSeq[Nothing]{def dropRight(n: Int): scala.collection.immutable.Seq[Nothing] with scala.collection.AbstractSeq[Nothing]; def takeRight(n: Int): scala.collection.immutable.Seq[Nothing] with scala.collection.AbstractSeq[Nothing]; def drop(n: Int): scala.collecti...
+x: List[scala.collection.immutable.Seq[Nothing] with scala.collection.AbstractSeq[Nothing] with java.io.Serializable] = List(List(), Vector())
+
 scala> 
 
 scala>