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* Fix and simplify typedTypeConstructor.Paul Phillips2012-12-281-1/+1
| | | | | | | | | | | | | | | | | | | | | | | | Investigating the useful output of devWarning (-Xdev people, it's good for you) led back to this comment: "normalize to get rid of type aliases" You may know that this is not all the normalizing does. Normalizing also turns TypeRefs with unapplied arguments (type constructors) into PolyTypes. That means that when typedParentType would call typedTypeConstructor it would find its parent had morphed into a PolyType. Not that it noticed; it would blithely continue and unwittingly discard the type arguments by way of appliedType (which smoothly logged the incident, thank you appliedType.) The simplification of typedTypeConstructor: There was a whole complicated special treatment of AnyRef here which appears to have become unnecessary. Removed special treatment and lit a candle for regularity. Updated lots of tests regarding newly not-so-special AnyRef.
* Selective dealiasing when printing errors.Paul Phillips2011-10-031-1/+1
| | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | *** Important note for busy commit log skimmers *** Symbol method "fullName" has been trying to serve the dual role of "how to print a symbol" and "how to find a class file." It cannot serve both these roles simultaneously, primarily because of package objects but other little things as well. Since in the majority of situations we want the one which corresponds to the idealized scala world, not the grubby bytecode, I went with that for fullName. When you require the path to a class (e.g. you are calling Class.forName) you should use javaClassName. package foo { package object bar { class Bippy } } If sym is Bippy's symbol, then sym.fullName == foo.bar.Bippy sym.javaClassName == foo.bar.package.Bippy *** End important note *** There are many situations where we (until now) forewent revealing everything we knew about a type mismatch. For instance, this isn't very helpful of scalac (at least in those more common cases where you didn't define type X on the previous repl line.) scala> type X = Int defined type alias X scala> def f(x: X): Byte = x <console>:8: error: type mismatch; found : X required: Byte def f(x: X): Byte = x ^ Now it says: found : X (which expands to) Int required: Byte def f(x: X): Byte = x ^ In addition I rearchitected a number of methods involving: - finding a symbol's owner - calculating a symbol's name - determining whether to print a prefix No review.
* One last batch of test cleanups and I think I'l...Paul Phillips2010-10-031-0/+4
One last batch of test cleanups and I think I'll call it a day. If you're worried I didn't leave any for anyone else, let me put your fears to rest. PLENTY left to sift through. No review.