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As demonstrated by the attached test, hyperlinking on constructor's
default arg doesn't work (the returned tree is the parameter tree,
i.e., `f`, which is of course wrong).
Printing the tree reveals the issue:
``
[[syntax trees at end of typer]] // Foo.scala
[0:63]package [0:0]<empty> {
[0:37]class Baz extends [9:37][39]scala.AnyRef {
[10:31]<paramaccessor> private[this] val f: [14]Int = _;
[14]<stable> <accessor> <paramaccessor> def f: [14]Int = [14][14]Baz.this.f;
[39]def <init>([14]f: [17]<type: [17]scala.Int> = [30]B.a): [9]Baz = [39]{
[39][39][39]Baz.super.<init>();
[9]()
}
};
[6]<synthetic> object Baz extends [6][6]AnyRef {
[6]def <init>(): [9]Baz.type = [6]{
[6][6][6]Baz.super.<init>();
[9]()
};
[14]<synthetic> def <init>$default$1: [14]Int = [30]B.a
};
[39:63]object B extends [48:63][63]scala.AnyRef {
[63]def <init>(): [48]B.type = [63]{
[63][63][63]B.super.<init>();
[48]()
};
[52:61]private[this] val a: [56]Int = [60:61]2;
[56]<stable> <accessor> def a: [56]Int = [56][56]B.this.a
}
}
``
In short, the default argument in `<init>` (the constructor) has an
offset position, while we would expect it to have a range position.
Therefore, when locating a tree for any position between (start=) 10
and (end=) 31, the paramaccessor tree `f` is returned.
The next commit will correct the problem.
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