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-rw-r--r--nuttx/lib/math/lib_sqrt.c116
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diff --git a/nuttx/lib/math/lib_sqrt.c b/nuttx/lib/math/lib_sqrt.c
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+/*
+ * Copyright (C) 2009-2011 Nick Johnson <nickbjohnson4224 at gmail.com>
+ *
+ * Permission to use, copy, modify, and distribute this software for any
+ * purpose with or without fee is hereby granted, provided that the above
+ * copyright notice and this permission notice appear in all copies.
+ *
+ * THE SOFTWARE IS PROVIDED "AS IS" AND THE AUTHOR DISCLAIMS ALL WARRANTIES
+ * WITH REGARD TO THIS SOFTWARE INCLUDING ALL IMPLIED WARRANTIES OF
+ * MERCHANTABILITY AND FITNESS. IN NO EVENT SHALL THE AUTHOR BE LIABLE FOR
+ * ANY SPECIAL, DIRECT, INDIRECT, OR CONSEQUENTIAL DAMAGES OR ANY DAMAGES
+ * WHATSOEVER RESULTING FROM LOSS OF USE, DATA OR PROFITS, WHETHER IN AN
+ * ACTION OF CONTRACT, NEGLIGENCE OR OTHER TORTIOUS ACTION, ARISING OUT OF
+ * OR IN CONNECTION WITH THE USE OR PERFORMANCE OF THIS SOFTWARE.
+ */
+
+#include <stdint.h>
+#include <float.h>
+#include <errno.h>
+#include <apps/math.h>
+
+static float __sqrt_approx(float x) {
+ int32_t i;
+
+ // floats + bit manipulation = +inf fun!
+ i = *((int32_t*) &x);
+ i = 0x1FC00000 + (i >> 1);
+ x = *((float*) &i);
+
+ return x;
+}
+
+float sqrtf(float x) {
+ float y;
+
+ // filter out invalid/trivial inputs
+ if (x < 0.0) { errno = EDOM; return NAN; }
+ if (isnan(x)) return NAN;
+ if (isinf(x)) return INFINITY;
+ if (x == 0.0) return 0.0;
+
+ // guess square root (using bit manipulation)
+ y = __sqrt_approx(x);
+
+ // perform three iterations of approximation
+ // this number (3) is definitely optimal
+ y = 0.5 * (y + x / y);
+ y = 0.5 * (y + x / y);
+ y = 0.5 * (y + x / y);
+
+ return y;
+}
+
+double sqrt(double x) {
+ long double y, y1;
+
+ // filter out invalid/trivial inputs
+ if (x < 0.0) { errno = EDOM; return NAN; }
+ if (isnan(x)) return NAN;
+ if (isinf(x)) return INFINITY;
+ if (x == 0.0) return 0.0;
+
+ // guess square root (using bit manipulation)
+ y = __sqrt_approx(x);
+
+ // perform four iterations of approximation
+ // this number (4) is definitely optimal
+ y = 0.5 * (y + x / y);
+ y = 0.5 * (y + x / y);
+ y = 0.5 * (y + x / y);
+ y = 0.5 * (y + x / y);
+
+ // if guess was terribe (out of range of float)
+ // repeat approximation until convergence
+ if (y * y < x - 1.0 || y * y > x + 1.0) {
+ y1 = -1.0;
+ while (y != y1) {
+ y1 = y;
+ y = 0.5 * (y + x / y);
+ }
+ }
+
+ return y;
+}
+
+long double sqrtl(long double x) {
+ long double y, y1;
+
+ // filter out invalid/trivial inputs
+ if (x < 0.0) { errno = EDOM; return NAN; }
+ if (isnan(x)) return NAN;
+ if (isinf(x)) return INFINITY;
+ if (x == 0.0) return 0.0;
+
+ // guess square root (using bit manipulation)
+ y = __sqrt_approx(x);
+
+ // perform four iterations of approximation
+ // this number (4) is definitely optimal
+ y = 0.5 * (y + x / y);
+ y = 0.5 * (y + x / y);
+ y = 0.5 * (y + x / y);
+ y = 0.5 * (y + x / y);
+
+ // if guess was terribe (out of range of float)
+ // repeat approximation until convergence
+ if (y * y < x - 1.0 || y * y > x + 1.0) {
+ y1 = -1.0;
+ while (y != y1) {
+ y1 = y;
+ y = 0.5 * (y + x / y);
+ }
+ }
+
+ return y;
+}