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t900.scala:4: error: type mismatch;
found : Foo.this.x.type (with underlying type Foo.this.bar)
required: AnyRef
Note that bar is unbounded, which means AnyRef is not a known parent.
Such types can participate in value classes, but instances
cannot appear in singleton types or in reference comparisons.
def break(): x.type
^
one error found
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